Perimeter of Rhombus
Perimeter of Rhombus
Perimeter of A Rhombus:
First, all four sides of a rhombus are equal, meaning that if we find one side, we can simply multiply the side by four to find the perimeter.
Second, the diagonals of a rhombus are perpendicular bisectors of each other, thus giving us four right triangles and splitting each diagonal in half. Using Pythagorean Theorem on any one of them will give us the length of our sides.
Illustration: If the area of rhombus be 24 and one of its diagonals be 4 cm, find the perimeter of rhombus.
Solution :Let ABCD be a rhombus such that its one diagonals AC = 4 cm. Support the diagonals AC and BD intersect at O. We have, Area of rhombus ABCD = 24
Hence BD = 12cm. Thus, we have AC = 4 cm and BD = 12 cm
and
Since the diagonals of a rhombus bisect each other at right angle. Therefore, OAB is right triangle, right angled at O. Using Pythagoras theorem in
AOB, we have
=
+
=
+
= 4 + 36 = 40
If the area of a rhombus is 24 cm and one of its diagonal is 8 cm, the perimeter is: | |||
| Right Option : B | |||
| View Explanation | |||
The perimeter of a rhombus is 160 cm and one diagonal is 10 cm long, then the length of the other diagonal is _________________. | |||
| Right Option : C | |||
| View Explanation | |||
Calculate the perimeter of a rhombus with each side measuring 12 units. | |||
| Right Option : A | |||
| View Explanation | |||
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